Caroline Wozniacki can look forward to a reunion with an old rivalinde in the third round of grand slam tournament Australian Open.
the Dane going up against Russian Maria Sharapova, who has five grand slam victories to his rich cv.
The 31-year-old freshman had no problems with his Swedish opponent Rebecca Peterson in the second round. The swede was beaten in two sets with the clear digits 6-2, 6-1.
In the first set broke Sharapova svenskerens serv the first time at 2-1, and after yet another servegennembrud for the position 5-2 could the Russian serve the set home.
the Dominance continued from the second problem introduction, where Sharapova broke peterson's serveparti two more times and brought himself comfortably in front 4-0.
Sharapova kept with great difficulty his own serve at 5-1, but broke the then peterson's serv clean and he won the match in two clear sets.
Wozniacki and Sharapova have met ten times in the past, and it's Sharapova who can boast of a little use. She has won six times on the She four.
however, It is doubtful how much statistics can be used to. Last mutual meeting must be all the way back to april 2015, to find.
In the meantime, have the two players been in ordkrig outside of the track.
Wozniacki has repeatedly spoken out critically about that Sharapova got wildcards to tournaments immediately after having served his suspension for the use of the banned substance meldonium.
There is laid up for a bit of a bang in the next round. Photo: Ritzau Scanpix